How to generate first N Hexagonal numbers in Java?

Problem Description :

Write a program in Java that generates first N hexagonal numbers.

First N Hexagonal numbers

Concept :

We can generate Nth hexagonal number using below formula.

N(2N-1)

For example - first 6 hexagonal numbers are 1, 6, 15, 28, 45, 66.

Hexagonal Numbers

Java Program :

package com.javamultiplex.number; import java.util.Scanner; /** * * @author Rohit Agarwal * @category Number Questions * @level Basic * @problem How to generate first N hexagonal numbers? * */ public class HexagonalNumbers { public static void main(String[] args) { Scanner input = null; try { input = new Scanner(System.in); System.out.println("Enter value of N : "); int limit = input.nextInt(); int hexagonal = 0; System.out.println("Hexagonal numbers are : "); for (int n = 1; n <= limit; n++) { hexagonal = n * (2 * n - 1); System.out.print(hexagonal + " "); } } finally { if (input != null) { input.close(); } } } }

Output :

Output - How to generate first n hexagonal numbers in Java?

References :

https://en.wikipedia.org/wiki/Hexagonal_number

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Tags : Hexagonal numbers in Java, Solution in Java, Mathematics problems, for loop, if else statement.

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