How to generate first N Pentagonal numbers in Java?

Problem Description :

Write a program in Java that generates first N pentagonal numbers.

First N Pentagonal numbers

Concept :

We can generate Nth pentagonal number using below formula.

N(3N-1)/2

For example - first 6 pentagonal numbers are 1, 5, 12, 22, 35, 51.

Pentagonal Numbers

Java Program :

package com.javamultiplex.number; import java.util.Scanner; /** * * @author Rohit Agarwal * @category Number Questions * @level Basic * @problem How to generate first N pentagonal numbers? * */ public class PentagonalNumbers { public static void main(String[] args) { Scanner input = null; try { input = new Scanner(System.in); System.out.println("Enter value of N : "); int limit = input.nextInt(); int pentagonal = 0; System.out.println("Pentagonal numbers are : "); for (int n = 1; n <= limit; n++) { pentagonal = (n * (3 * n - 1)) / 2; System.out.print(pentagonal + " "); } } finally { if (input != null) { input.close(); } } } }

Output :

Output - How to generate first n pentagonal numbers in Java?

References :

https://en.wikipedia.org/wiki/Pentagonal_number

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Tags : Pentagonal numbers in Java, Solution in Java, Mathematics problems, for loop, if else statement.

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