How to generate first N Pentagonal numbers in Java?

Problem Description :

Write a program in Java that generates first N pentagonal numbers.

First N Pentagonal numbers

Concept :

We can generate Nth pentagonal number using below formula.

N(3N-1)/2

For example -  first 6 pentagonal numbers are 1, 5, 12, 22, 35, 51.

Pentagonal Numbers

Java Program :

	package com.javamultiplex.number;
	import java.util.Scanner;
	/**
	*
	* @author Rohit Agarwal
	* @category Number Questions
	* @level Basic
	* @problem How to generate first N pentagonal numbers?
	*
	*/
	public class PentagonalNumbers {
	public static void main(String[] args) {
	Scanner input = null;
	try {
	input = new Scanner(System.in);
	System.out.println("Enter value of N : ");
	int limit = input.nextInt();
	int pentagonal = 0;
	System.out.println("Pentagonal numbers are : ");
	for (int n = 1; n <= limit; n++) {
	pentagonal = (n * (3 * n - 1)) / 2;
	System.out.print(pentagonal + " ");
	}
	} finally {
	if (input != null) {
	input.close();
	}
	}
	}
	}

view raw PentagonalNumbers.java hosted with ❤ by GitHub

Output :

Output - How to generate first n pentagonal numbers in Java?

References :

https://en.wikipedia.org/wiki/Pentagonal_number

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Tags : Pentagonal numbers in Java, Solution in Java, Mathematics problems, for loop, if else statement.

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