How to generate first N triangular numbers in Java?

Problem Description :

Write a program in Java that generates first N triangular numbers.

First N Triangular numbers

Concept :

We can generate Nth triangular number or triangle number using below formula.

N(N+1)/2

For example - first 6 triangular numbers are 1, 3, 6, 10, 15, 21.

Java Program :

	package com.javamultiplex.number;
	import java.util.Scanner;
	/**
	*
	* @author Rohit Agarwal
	* @category Questions on Number
	* @problem How to generate first N triangular numbers?
	*
	*/
	public class TriangularNumbers {
	public static void main(String[] args) {
	Scanner input = null;
	try {
	input = new Scanner(System.in);
	System.out.println("Enter value of N : ");
	int limit = input.nextInt();
	int triangular = 0;
	System.out.println("Triangular numbers are : ");
	for (int n = 1; n <= limit; n++) {
	triangular = (n * (n + 1)) / 2;
	System.out.print(triangular + " ");
	}
	} finally {
	if (input != null) {
	input.close();
	}
	}
	}
	}

view raw TriangularNumbers.java hosted with ❤ by GitHub

Output :

Output - How to generate first n triangular numbers in Java?

References :

https://en.wikipedia.org/wiki/Triangular_number

http://www.9math.com/book/sum-first-n-natural-numbers

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Tags : Triangular numbers in Java, Solution in Java, Mathematics problems, for loop, if else statement, Sum of first n natural numbers.

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