How to generate first N triangular numbers in Java?

Problem Description :

Write a program in Java that generates first N triangular numbers.

First N Triangular numbers

Concept :

We can generate Nth triangular number or triangle number using below formula.

N(N+1)/2

For example - first 6 triangular numbers are 1, 3, 6, 10, 15, 21.

Java Program :

package com.javamultiplex.number; import java.util.Scanner; /** * * @author Rohit Agarwal * @category Questions on Number * @problem How to generate first N triangular numbers? * */ public class TriangularNumbers { public static void main(String[] args) { Scanner input = null; try { input = new Scanner(System.in); System.out.println("Enter value of N : "); int limit = input.nextInt(); int triangular = 0; System.out.println("Triangular numbers are : "); for (int n = 1; n <= limit; n++) { triangular = (n * (n + 1)) / 2; System.out.print(triangular + " "); } } finally { if (input != null) { input.close(); } } } }

Output :

Output - How to generate first n triangular numbers in Java?

References :

https://en.wikipedia.org/wiki/Triangular_number

http://www.9math.com/book/sum-first-n-natural-numbers

Thank you friends, I hope you have clearly understood the solution of this problem. If you have any doubt, suggestion or query please feel free to comment below. You can also discuss this solution in our forum.

Tags : Triangular numbers in Java, Solution in Java, Mathematics problems, for loop, if else statement, Sum of first n natural numbers.

About Author:

I am simple guy with lot of ambitions. My main motive is to share whatever knowledge I have related to programming. With me you can easily learn how to solve any programming problem in Java.You can connect with me on social networking sites also.

Let's Get Connected: Linkedin | Facebook | Google Plus