How to convert Binary number to Octal number in Java?
Problem Description :
Write a program in Java that converts Binary number to Octal number.
Concept :
For converting binary number to octal number. First, we have to convert binary number to decimal number and then decimal number to octal number.
Recommended :
Java Program :
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package com.javamultiplex.baseconversion; | |
import java.util.Scanner; | |
/** | |
* | |
* @author Rohit Agarwal | |
* @category Base Conversion | |
* @problem Convert Binary to Octal | |
* | |
*/ | |
public class BinaryToOctal { | |
public static void main(String[] args) { | |
Scanner input = null; | |
try { | |
input = new Scanner(System.in); | |
System.out.println("Enter binary number : "); | |
String number = input.next(); | |
if (isBinaryNumber(number)) { | |
String octal = getOctalFromBinaryNumber(number); | |
System.out.println("Octal Number : " + octal); | |
} else { | |
System.out.println("Please enter valid binary number."); | |
} | |
} finally { | |
if (input != null) { | |
input.close(); | |
} | |
} | |
} | |
private static String getOctalFromBinaryNumber(String number) { | |
// Convert Binary to Decimal. | |
int decimal = getDecimalFromBinaryNumber(number); | |
// Convert Decimal to Octal. | |
String octal = getOctalFromDecimalNumber(decimal); | |
return octal; | |
} | |
private static String getOctalFromDecimalNumber(int decimal) { | |
int remainder = 0; | |
StringBuilder octal = new StringBuilder(); | |
while (decimal != 0) { | |
remainder = decimal % 8; | |
// Converting Integer to String and adding into StringBuilder. | |
octal.append(String.valueOf(remainder)); | |
decimal = decimal / 8; | |
} | |
// Reverse String using library function of StringBuilder class. | |
return octal.reverse().toString(); | |
} | |
private static int getDecimalFromBinaryNumber(String number) { | |
// Converting String to StringBuilder. | |
StringBuilder string = new StringBuilder(number); | |
string = string.reverse(); | |
int length = string.length(); | |
int digit, power, sum = 0; | |
for (int i = 0; i < length; i++) { | |
digit = string.charAt(i) - 48; | |
power = (int) Math.pow(2, i); | |
sum = sum + digit * power; | |
} | |
return sum; | |
} | |
private static boolean isBinaryNumber(String number) { | |
/* | |
* Regular expression that matches string containing only binary | |
* digits[0-1]. | |
*/ | |
String pattern = "^[01]+$"; | |
boolean result = false; | |
if (number.matches(pattern)) { | |
result = true; | |
} | |
return result; | |
} | |
} |
Output :
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Output - How to convert Binary number to Octal number in Java? |
References :
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Tags : Conversion problems, Binary to Octal, Solution in Java, String, StringBuilder, Regular expressions, while loop, for loop, if else statement.
How to convert Binary number to Octal number in Java?
Reviewed by Rohit Agarwal
on
11/17/2016
Rating:

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