How to convert Octal number to Binary number in Java?
Problem Description :
Write a program in Java that converts Octal number to Binary number.
Concept :
For converting octal number to binary number. First, we have to convert octal number to decimal number and then decimal number to binary number.
Octal -> Decimal -> Binary
Recommended :
Java Program :
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package com.javamultiplex.baseconversion; | |
import java.util.Scanner; | |
/** | |
* | |
* @author Rohit Agarwal | |
* @category Base Conversion | |
* @problem Convert Octal to Binary | |
* | |
*/ | |
public class OctalToBinary { | |
public static void main(String[] args) { | |
Scanner input = null; | |
try { | |
input = new Scanner(System.in); | |
System.out.println("Enter octal number : "); | |
String number = input.next(); | |
if (isOctalNumber(number)) { | |
String binary = getBinaryFromOctalNumber(number); | |
System.out.println("Binary Number : " + binary); | |
} else { | |
System.out.println("Please enter valid octal number."); | |
} | |
} finally { | |
if (input != null) { | |
input.close(); | |
} | |
} | |
} | |
private static String getBinaryFromOctalNumber(String number) { | |
// Convert Octal to Decimal | |
int decimal = getDecimalFromOctalNumber(number); | |
// Convert Decimal to Binary | |
String binary = getBinaryFromDecimalNumber(decimal); | |
return binary; | |
} | |
private static String getBinaryFromDecimalNumber(int decimal) { | |
int remainder = 0; | |
StringBuilder binary = new StringBuilder(); | |
while (decimal != 0) { | |
remainder = decimal % 2; | |
// Converting Integer to String and adding into StringBuilder. | |
binary.append(String.valueOf(remainder)); | |
decimal = decimal / 2; | |
} | |
// Reverse String using library function of StringBuilder class. | |
return binary.reverse().toString(); | |
} | |
private static int getDecimalFromOctalNumber(String number) { | |
// Converting String to StringBuilder. | |
StringBuilder string = new StringBuilder(number); | |
string = string.reverse(); | |
int length = string.length(); | |
int digit, power, sum = 0; | |
for (int i = 0; i < length; i++) { | |
digit = string.charAt(i) - 48; | |
power = (int) Math.pow(8, i); | |
sum = sum + digit * power; | |
} | |
return sum; | |
} | |
private static boolean isOctalNumber(String number) { | |
/* | |
* Regular expression that matches string containing only octal | |
* digits[0-7]. | |
*/ | |
String pattern = "^[0-7]+$"; | |
boolean result = false; | |
if (number.matches(pattern)) { | |
result = true; | |
} | |
return result; | |
} | |
} |
Output :
References :
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Tags : Conversion problems, Octal to Binary, Solution in Java, Regular expressions, String, StringBuilder, if else statement, while loop, for loop.
How to convert Octal number to Binary number in Java?
Reviewed by Rohit Agarwal
on
11/20/2016
Rating:

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