How to check whether given number is Octal or not in Java?

Problem Description :

Write a program in Java that checks whether given number is Octal or not? Do all possible validations also.

Given number is octal or not?

Concept :

An octal number is a number that is represented using eight distinct symbols 0-7 where these symbols represent values zero to seven.

Java Program :

	package com.javamultiplex.number;
	import java.util.Scanner;
	/**
	*
	* @author Rohit Agarwal
	* @category Number Problems
	* @problem Number is octal or not
	*
	*/
	public class OctalNumber {
	public static void main(String[] args) {
	Scanner input = null;
	try {
	input = new Scanner(System.in);
	System.out.println("Enter number : ");
	String number = input.next();
	/*
	* Regular expression that matches string containing only
	* digits[0-9].
	*/
	String pattern1 = "^[0-9]+$";
	if (number.matches(pattern1)) {
	/*
	* Regular expression that matches string containing only octal
	* digits[0-7].
	*/
	String pattern2 = "^[0-7]+$";
	if (number.matches(pattern2)) {
	System.out.println("It is octal.");
	} else {
	System.out.println("It is not octal.");
	}
	} else {
	System.out.println("Please enter valid number.");
	}
	} finally {
	if (input != null) {
	input.close();
	}
	}
	}
	}

view raw OctalNumber.java hosted with ❤ by GitHub

Output :

Case 1 :

Output - Given number is octal

Case 2 :

Output - Given number is not octal

References :

https://en.wikipedia.org/wiki/Octal

https://en.wikipedia.org/wiki/Regular_expression

http://docs.oracle.com/javase/7/docs/api/java/lang/String.html

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Tags : Octal numbers, Solution in Java, Regular expressions, String, if else statement.

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