How to check whether given number is Hexadecimal or not in Java?
Problem Description :
Write a program in java that checks whether given number is Hexadecimal or not? Do all possible validations also.
Concept :
A hexadecimal number is a number that is represented using sixteen distinct symbols, where symbol 0-9 represent values zero to nine and symbols A,B,C,D,E,F (alternatively a,b,c,d,e,f) represent values ten to fifteen.
Java Program :
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package com.javamultiplex.number; | |
import java.util.Scanner; | |
/** | |
* | |
* @author Rohit Agarwal | |
* @category Number Problems | |
* @problem Number is hexadecimal or not | |
* | |
*/ | |
public class HexadecimalNumber { | |
public static void main(String[] args) { | |
Scanner input = null; | |
try { | |
input = new Scanner(System.in); | |
System.out.println("Enter number : "); | |
String number = input.next(); | |
/* | |
* Regular expression that matches string containing digits [0-9] | |
* and alphabets [A-F] or [a-f]. | |
*/ | |
String pattern1 = "^[0-9A-Fa-f]+$"; | |
if (number.matches(pattern1)) { | |
System.out.println("It is hexadecimal"); | |
} else { | |
System.out.println("It is not hexadecimal."); | |
} | |
} finally { | |
if (input != null) { | |
input.close(); | |
} | |
} | |
} | |
} |
Output :
References :
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Tags : Hexadecimal numbers, Solution in Java, Regular expressions, String, if else statement.
How to check whether given number is Hexadecimal or not in Java?
Reviewed by Rohit Agarwal
on
11/12/2016
Rating:

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