How to check whether given number is Hexadecimal or not in Java?

Problem Description :

Write a program in java that checks whether given number is Hexadecimal or not? Do all possible validations also.

Given number is hexadecimal or not?

Concept :

A hexadecimal number is a number that is represented using sixteen distinct symbols, where symbol 0-9 represent values zero to nine and symbols A,B,C,D,E,F (alternatively a,b,c,d,e,f) represent values ten to fifteen.

Java Program :

package com.javamultiplex.number; import java.util.Scanner; /** * * @author Rohit Agarwal * @problem Number is hexadecimal or not * */ public class HexadecimalNumber { public static void main(String[] args) { Scanner input = null; try { input = new Scanner(System.in); System.out.println("Enter number : "); String number = input.next(); /* * Regular expression that matches string containing digits [0-9] * and alphabets [A-F] or [a-f]. */ String pattern1 = "^[0-9A-Fa-f]+$"; if (number.matches(pattern1)) { System.out.println("It is hexadecimal"); } else { System.out.println("It is not hexadecimal."); } } finally { if (input != null) { input.close(); } } } }

Output :

Case 1 :

Output - Given number is hexadecimal.

Case 2 :

Output - Given number is not hexadecimal.

References :

https://en.wikipedia.org/wiki/Hexadecimal

https://en.wikipedia.org/wiki/Regular_expression

http://docs.oracle.com/javase/7/docs/api/java/lang/String.html

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Tags : Hexadecimal numbers, Solution in Java, Regular expressions, String, if else statement.

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