How to convert Hexadecimal number to Binary number in Java?

Problem Description :

Write a program in Java that converts Hexadecimal number to Binary number.

Java program that converts hexadecimal number to binary number.

Hexadecimal to Binary conversion

Concept :

For converting hexadecimal number to binary number. First, we have to convert hexadecimal number to decimal number and then decimal number to binary number.

Hexadecimal -> Decimal -> Binary

Java Program :

package com.javamultiplex.baseconversion; import java.util.Scanner; /** * * @author Rohit Agarwal * @category Base Conversion * @problem Convert Hexadecimal to Binary * */ public class HexadecimalToBinary { public static void main(String[] args) { Scanner input = null; try { input = new Scanner(System.in); System.out.println("Enter hexadecimal number : "); String number = input.next(); if (isHexadecimalNumber(number)) { String binary = getBinaryFromHexadecimalNumber(number); System.out.println("Binary Number : " + binary); } else { System.out.println("Please enter valid hexadecimal number."); } } finally { if (input != null) { input.close(); } } } private static String getBinaryFromHexadecimalNumber(String number) { // Convert Hexadecimal to Decimal int decimal = getDecimalFromHexadecimalNumber(number); // Convert Decimal to Binary String binary = getBinaryFromDecimalNumber(decimal); return binary; } private static String getBinaryFromDecimalNumber(int decimal) { int remainder = 0; StringBuilder binary = new StringBuilder(); while (decimal != 0) { remainder = decimal % 2; // Converting Integer to String and adding into StringBuilder. binary.append(String.valueOf(remainder)); decimal = decimal / 2; } // Reverse String using library function of StringBuilder class. return binary.reverse().toString(); } private static int getDecimalFromHexadecimalNumber(String number) { // Converting String to StringBuilder. StringBuilder string = new StringBuilder(number); string = string.reverse(); int length = string.length(); int digit, power, sum = 0; for (int i = 0; i < length; i++) { if (Character.isDigit(string.charAt(i))) { digit = string.charAt(i) - 48; } else { digit = getHexadecimalCharacterDigit(string.charAt(i)); } power = (int) Math.pow(16, i); sum = sum + digit * power; } return sum; } private static int getHexadecimalCharacterDigit(char ch) { int digit = 0; switch (ch) { case 'A': case 'a': digit = 10; break; case 'B': case 'b': digit = 11; break; case 'C': case 'c': digit = 12; break; case 'D': case 'd': digit = 13; break; case 'E': case 'e': digit = 14; break; case 'F': case 'f': digit = 15; break; } return digit; } private static boolean isHexadecimalNumber(String number) { /* * Regular expression that matches string containing only digits [0-9] * and alphabets [A-F] or [a-f] */ String pattern = "^[0-9a-fA-F]+$"; boolean result = false; if (number.matches(pattern)) { result = true; } return result; } }

Output :

Output - How to convert Hexadecimal number to Binary number in Java?

References :

https://en.wikipedia.org/wiki/Regular_expression

http://docs.oracle.com/javase/7/docs/api/java/lang/String.html

https://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html

Thank you friends, I hope you have clearly understood the solution of this problem. If you have any doubt, suggestion or query please feel free to comment below. You can also discuss this solution in our forum.

Tags : Conversion problems, Hexadecimal to Binary, Solution in Java, String, StringBuilder, Regular expressions, switch statement, if else statement, for loop, while loop.

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How to convert Hexadecimal number to Binary number in Java?

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