How to convert Binary number to Hexadecimal number in Java?

Problem Description :

Write a program in Java that converts Binary number to Hexadecimal number.

Java program that converts binary number to hexadecimal number.

Binary to Hexadecimal conversion

Concept :

For converting binary number to hexadecimal number. First, we have to convert binary number to decimal number and then decimal number to hexadecimal number.

Binary -> Decimal ->Hexadecimal

Java Program :

package com.javamultiplex.baseconversion; import java.util.Scanner; /** * * @author Rohit Agarwal * @category Base Conversion * @problem Convert Binary to Hexadecimal * */ public class BinaryToHexadecimal { public static void main(String[] args) { Scanner input = null; try { input = new Scanner(System.in); System.out.println("Enter binary number : "); String number = input.next(); if (isBinaryNumber(number)) { String hexadecimal = getHexadecimalFromBinaryNumber(number); System.out.println("Hexadecimal Number : " + hexadecimal); } else { System.out.println("Please enter valid binary number."); } } finally { if (input != null) { input.close(); } } } private static String getHexadecimalFromBinaryNumber(String number) { // Convert Binary to Decimal int decimal = getDecimalFromBinaryNumber(number); // Convert Decimal to Hexadecimal String hexadecimal = getHexadecimalFromDecimalNumber(decimal); return hexadecimal; } private static String getHexadecimalFromDecimalNumber(int decimal) { int remainder = 0; StringBuilder hexadecimal = new StringBuilder(); String result; while (decimal != 0) { remainder = decimal % 16; if (remainder >= 10 && remainder <= 15) { char hexChar = getHexadecimalCharacter(remainder); // Convert char to String. result = String.valueOf(hexChar); } else { // Convert int to String. result = String.valueOf(remainder); } // Add string to StringBuilder. hexadecimal.append(String.valueOf(result)); decimal = decimal / 16; } // Reverse String using library function of StringBuilder class. return hexadecimal.reverse().toString(); } private static char getHexadecimalCharacter(int remainder) { char ch = '\u0000'; switch (remainder) { case 10: ch = 'A'; break; case 11: ch = 'B'; break; case 12: ch = 'C'; break; case 13: ch = 'D'; break; case 14: ch = 'E'; break; case 15: ch = 'F'; break; } return ch; } private static int getDecimalFromBinaryNumber(String number) { //Converting String to StringBuilder. StringBuilder string = new StringBuilder(number); string = string.reverse(); int length = string.length(); int digit, power, sum = 0; for (int i = 0; i < length; i++) { digit = string.charAt(i) - 48; power = (int) Math.pow(2, i); sum = sum + digit * power; } return sum; } private static boolean isBinaryNumber(String number) { /* * Regular expression that matches string containing only binary * digits[0-1]. */ String pattern = "^[01]+$"; boolean result = false; if (number.matches(pattern)) { result = true; } return result; } }

Output :

Output - How to convert Binary number to Hexadecimal number in Java?

References :

https://en.wikipedia.org/wiki/Regular_expression

http://docs.oracle.com/javase/7/docs/api/java/lang/String.html

https://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html

Thank you friends, I hope you have clearly understood the solution of this problem. If you have any doubt, suggestion or query please feel free to comment below. You can also discuss this solution in our forum.

Tags : Conversion problems, Binary to Hexadecimal, Solution in Java, String, StringBuilder, Regular expressions, if else statement, for loop, while loop, switch statement.

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How to convert Binary number to Hexadecimal number in Java?

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