How to convert Hexadecimal number to Octal number in Java?
Problem Description :
Write a program in Java that converts Hexadecimal number to Octal number.
Concept :
For converting hexadecimal number to octal number. First, we have to convert hexadecimal number to decimal number and then decimal number to octal number.
Hexadecimal -> Decimal -> Octal
Recommended :
Java Program :
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package com.javamultiplex.baseconversion; | |
import java.util.Scanner; | |
/** | |
* | |
* @author Rohit Agarwal | |
* @category Base Conversion | |
* @problem Convert Hexadecimal to Octal | |
* | |
*/ | |
public class HexadecimalToOctal { | |
public static void main(String[] args) { | |
Scanner input = null; | |
try { | |
input = new Scanner(System.in); | |
System.out.println("Enter hexadecimal number : "); | |
String number = input.next(); | |
if (isHexadecimalNumber(number)) { | |
String octal = getOctalFromHexadecimalNumber(number); | |
System.out.println("Octal Number : " + octal); | |
} else { | |
System.out.println("Please enter valid hexadecimal number."); | |
} | |
} finally { | |
if (input != null) { | |
input.close(); | |
} | |
} | |
} | |
private static String getOctalFromHexadecimalNumber(String number) { | |
// Convert Hexadecimal to Decimal | |
int decimal = getDecimalFromHexadecimalNumber(number); | |
// Convert Decimal to Octal | |
String octal = getOctalFromDecimalNumber(decimal); | |
return octal; | |
} | |
private static String getOctalFromDecimalNumber(int decimal) { | |
int remainder = 0; | |
StringBuilder octal = new StringBuilder(); | |
while (decimal != 0) { | |
remainder = decimal % 8; | |
// Converting Integer to String and adding into StringBuilder. | |
octal.append(String.valueOf(remainder)); | |
decimal = decimal / 8; | |
} | |
// Reverse String using library function of StringBuilder class. | |
return octal.reverse().toString(); | |
} | |
private static int getDecimalFromHexadecimalNumber(String number) { | |
// Converting String to StringBuilder. | |
StringBuilder string = new StringBuilder(number); | |
string = string.reverse(); | |
int length = string.length(); | |
int digit, power, sum = 0; | |
for (int i = 0; i < length; i++) { | |
if (Character.isDigit(string.charAt(i))) { | |
digit = string.charAt(i) - 48; | |
} else { | |
digit = getHexadecimalCharacterDigit(string.charAt(i)); | |
} | |
power = (int) Math.pow(16, i); | |
sum = sum + digit * power; | |
} | |
return sum; | |
} | |
private static int getHexadecimalCharacterDigit(char ch) { | |
int digit = 0; | |
switch (ch) { | |
case 'A': | |
case 'a': | |
digit = 10; | |
break; | |
case 'B': | |
case 'b': | |
digit = 11; | |
break; | |
case 'C': | |
case 'c': | |
digit = 12; | |
break; | |
case 'D': | |
case 'd': | |
digit = 13; | |
break; | |
case 'E': | |
case 'e': | |
digit = 14; | |
break; | |
case 'F': | |
case 'f': | |
digit = 15; | |
break; | |
} | |
return digit; | |
} | |
private static boolean isHexadecimalNumber(String number) { | |
/* | |
* Regular expression that matches string containing only digits [0-9] | |
* and alphabets [A-F] or [a-f] | |
*/ | |
String pattern = "^[0-9a-fA-F]+$"; | |
boolean result = false; | |
if (number.matches(pattern)) { | |
result = true; | |
} | |
return result; | |
} | |
} |
Output :
References :
Thank you friends, I hope you have clearly understood the solution of this problem. If you have any doubt, suggestion or query please feel free to comment below. You can also discuss this solution in our forum.
Tags : Conversion problems, Hexadecimal to Octal, Solution in Java, String, StringBuilder, Regular expressions, switch statement, for loop, while loop, if else statement.
How to convert Hexadecimal number to Octal number in Java?
Reviewed by Rohit Agarwal
on
11/23/2016
Rating:

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